3(v+4)=-2(7v-3)+3v

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Solution for 3(v+4)=-2(7v-3)+3v equation: 



3(v+4)=-2(7v-3)+3v

We move all terms to the left:

3(v+4)-(-2(7v-3)+3v)=0

We multiply parentheses

3v-(-2(7v-3)+3v)+12=0



We calculate terms in parentheses: -(-2(7v-3)+3v), so:

-2(7v-3)+3v

We add all the numbers together, and all the variables

3v-2(7v-3)

We multiply parentheses

3v-14v+6

We add all the numbers together, and all the variables

-11v+6

Back to the equation:

-(-11v+6)



We get rid of parentheses

3v+11v-6+12=0

We add all the numbers together, and all the variables

14v+6=0

We move all terms containing v to the left, all other terms to the right

14v=-6

v=-6/14

v=-3/7

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