3(v+4)=-3(4v-3)+6v

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Solution for 3(v+4)=-3(4v-3)+6v equation: 



3(v+4)=-3(4v-3)+6v

We move all terms to the left:

3(v+4)-(-3(4v-3)+6v)=0

We multiply parentheses

3v-(-3(4v-3)+6v)+12=0



We calculate terms in parentheses: -(-3(4v-3)+6v), so:

-3(4v-3)+6v

We add all the numbers together, and all the variables

6v-3(4v-3)

We multiply parentheses

6v-12v+9

We add all the numbers together, and all the variables

-6v+9

Back to the equation:

-(-6v+9)



We get rid of parentheses

3v+6v-9+12=0

We add all the numbers together, and all the variables

9v+3=0

We move all terms containing v to the left, all other terms to the right

9v=-3

v=-3/9

v=-1/3

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