3(v+4)=-6(3v-1)+9v

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Solution for 3(v+4)=-6(3v-1)+9v equation: 



3(v+4)=-6(3v-1)+9v

We move all terms to the left:

3(v+4)-(-6(3v-1)+9v)=0

We multiply parentheses

3v-(-6(3v-1)+9v)+12=0



We calculate terms in parentheses: -(-6(3v-1)+9v), so:

-6(3v-1)+9v

We add all the numbers together, and all the variables

9v-6(3v-1)

We multiply parentheses

9v-18v+6

We add all the numbers together, and all the variables

-9v+6

Back to the equation:

-(-9v+6)



We get rid of parentheses

3v+9v-6+12=0

We add all the numbers together, and all the variables

12v+6=0

We move all terms containing v to the left, all other terms to the right

12v=-6

v=-6/12

v=-1/2

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