3(v+5)=-2(9v-4)+7v

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Solution for 3(v+5)=-2(9v-4)+7v equation: 



3(v+5)=-2(9v-4)+7v

We move all terms to the left:

3(v+5)-(-2(9v-4)+7v)=0

We multiply parentheses

3v-(-2(9v-4)+7v)+15=0



We calculate terms in parentheses: -(-2(9v-4)+7v), so:

-2(9v-4)+7v

We add all the numbers together, and all the variables

7v-2(9v-4)

We multiply parentheses

7v-18v+8

We add all the numbers together, and all the variables

-11v+8

Back to the equation:

-(-11v+8)



We get rid of parentheses

3v+11v-8+15=0

We add all the numbers together, and all the variables

14v+7=0

We move all terms containing v to the left, all other terms to the right

14v=-7

v=-7/14

v=-1/2

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