3(v+5)=-3(7-11v)+6

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Solution for 3(v+5)=-3(7-11v)+6 equation: 



3(v+5)=-3(7-11v)+6

We move all terms to the left:

3(v+5)-(-3(7-11v)+6)=0

We add all the numbers together, and all the variables

3(v+5)-(-3(-11v+7)+6)=0

We multiply parentheses

3v-(-3(-11v+7)+6)+15=0



We calculate terms in parentheses: -(-3(-11v+7)+6), so:

-3(-11v+7)+6

We multiply parentheses

33v-21+6

We add all the numbers together, and all the variables

33v-15

Back to the equation:

-(33v-15)



We get rid of parentheses

3v-33v+15+15=0

We add all the numbers together, and all the variables

-30v+30=0

We move all terms containing v to the left, all other terms to the right

-30v=-30

v=-30/-30

v=1

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