3(v-1)=3v+5-2(-4v-1)

Solution for 3(v-1)=3v+5-2(-4v-1) equation:

3(v-1)=3v+5-2(-4v-1)

We move all terms to the left:

3(v-1)-(3v+5-2(-4v-1))=0

We multiply parentheses

3v-(3v+5-2(-4v-1))-3=0


We calculate terms in parentheses: -(3v+5-2(-4v-1)), so:

3v+5-2(-4v-1)

determiningTheFunctionDomain
3v-2(-4v-1)+5

We multiply parentheses

3v+8v+2+5

We add all the numbers together, and all the variables

11v+7

Back to the equation:

-(11v+7)


We get rid of parentheses

3v-11v-7-3=0

We add all the numbers together, and all the variables

-8v-10=0

We move all terms containing v to the left, all other terms to the right

-8v=10

v=10/-8

v=-1+1/4