3(v-1)=3v+5-2(-4v-1)

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Solution for 3(v-1)=3v+5-2(-4v-1) equation:



3(v-1)=3v+5-2(-4v-1)
We move all terms to the left:
3(v-1)-(3v+5-2(-4v-1))=0
We multiply parentheses
3v-(3v+5-2(-4v-1))-3=0
We calculate terms in parentheses: -(3v+5-2(-4v-1)), so:
3v+5-2(-4v-1)
determiningTheFunctionDomain 3v-2(-4v-1)+5
We multiply parentheses
3v+8v+2+5
We add all the numbers together, and all the variables
11v+7
Back to the equation:
-(11v+7)
We get rid of parentheses
3v-11v-7-3=0
We add all the numbers together, and all the variables
-8v-10=0
We move all terms containing v to the left, all other terms to the right
-8v=10
v=10/-8
v=-1+1/4

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