3(v-1)=5v+1-2(-4-2)

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Solution for 3(v-1)=5v+1-2(-4-2) equation: 



3(v-1)=5v+1-2(-4-2)

We move all terms to the left:

3(v-1)-(5v+1-2(-4-2))=0

We add all the numbers together, and all the variables

3(v-1)-(5v+1-2(-6))=0

We multiply parentheses

3v-(5v+1-2(-6))-3=0



We calculate terms in parentheses: -(5v+1-2(-6)), so:

5v+1-2(-6)

We add all the numbers together, and all the variables

5v+13

Back to the equation:

-(5v+13)



We get rid of parentheses

3v-5v-13-3=0

We add all the numbers together, and all the variables

-2v-16=0

We move all terms containing v to the left, all other terms to the right

-2v=16

v=16/-2

v=-8

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