3(v-1)=5v+1-2(-4v-2)

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Solution for 3(v-1)=5v+1-2(-4v-2) equation: 



3(v-1)=5v+1-2(-4v-2)

We move all terms to the left:

3(v-1)-(5v+1-2(-4v-2))=0

We multiply parentheses

3v-(5v+1-2(-4v-2))-3=0



We calculate terms in parentheses: -(5v+1-2(-4v-2)), so:

5v+1-2(-4v-2)

determiningTheFunctionDomain
5v-2(-4v-2)+1

We multiply parentheses

5v+8v+4+1

We add all the numbers together, and all the variables

13v+5

Back to the equation:

-(13v+5)



We get rid of parentheses

3v-13v-5-3=0

We add all the numbers together, and all the variables

-10v-8=0

We move all terms containing v to the left, all other terms to the right

-10v=8

v=8/-10

v=-4/5

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