3(v-1)=5v+3-2(-3v-3)

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Solution for 3(v-1)=5v+3-2(-3v-3) equation: 



3(v-1)=5v+3-2(-3v-3)

We move all terms to the left:

3(v-1)-(5v+3-2(-3v-3))=0

We multiply parentheses

3v-(5v+3-2(-3v-3))-3=0



We calculate terms in parentheses: -(5v+3-2(-3v-3)), so:

5v+3-2(-3v-3)

determiningTheFunctionDomain
5v-2(-3v-3)+3

We multiply parentheses

5v+6v+6+3

We add all the numbers together, and all the variables

11v+9

Back to the equation:

-(11v+9)



We get rid of parentheses

3v-11v-9-3=0

We add all the numbers together, and all the variables

-8v-12=0

We move all terms containing v to the left, all other terms to the right

-8v=12

v=12/-8

v=-1+1/2

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