3(v-1)=v+3-2(-3v-4)

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Solution for 3(v-1)=v+3-2(-3v-4) equation: 



3(v-1)=v+3-2(-3v-4)

We move all terms to the left:

3(v-1)-(v+3-2(-3v-4))=0

We multiply parentheses

3v-(v+3-2(-3v-4))-3=0



We calculate terms in parentheses: -(v+3-2(-3v-4)), so:

v+3-2(-3v-4)

determiningTheFunctionDomain
v-2(-3v-4)+3

We multiply parentheses

v+6v+8+3

We add all the numbers together, and all the variables

7v+11

Back to the equation:

-(7v+11)



We get rid of parentheses

3v-7v-11-3=0

We add all the numbers together, and all the variables

-4v-14=0

We move all terms containing v to the left, all other terms to the right

-4v=14

v=14/-4

v=-3+1/2

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