3(v-2)-2=-4(-6v+3)-5v

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Solution for 3(v-2)-2=-4(-6v+3)-5v equation:



3(v-2)-2=-4(-6v+3)-5v
We move all terms to the left:
3(v-2)-2-(-4(-6v+3)-5v)=0
We multiply parentheses
3v-(-4(-6v+3)-5v)-6-2=0
We calculate terms in parentheses: -(-4(-6v+3)-5v), so:
-4(-6v+3)-5v
We add all the numbers together, and all the variables
-5v-4(-6v+3)
We multiply parentheses
-5v+24v-12
We add all the numbers together, and all the variables
19v-12
Back to the equation:
-(19v-12)
We add all the numbers together, and all the variables
3v-(19v-12)-8=0
We get rid of parentheses
3v-19v+12-8=0
We add all the numbers together, and all the variables
-16v+4=0
We move all terms containing v to the left, all other terms to the right
-16v=-4
v=-4/-16
v=1/4

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