3(v-2)-5=-5(-4v+3)-v

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Solution for 3(v-2)-5=-5(-4v+3)-v equation: 



3(v-2)-5=-5(-4v+3)-v

We move all terms to the left:

3(v-2)-5-(-5(-4v+3)-v)=0

We multiply parentheses

3v-(-5(-4v+3)-v)-6-5=0



We calculate terms in parentheses: -(-5(-4v+3)-v), so:

-5(-4v+3)-v

We add all the numbers together, and all the variables

-1v-5(-4v+3)

We multiply parentheses

-1v+20v-15

We add all the numbers together, and all the variables

19v-15

Back to the equation:

-(19v-15)



We add all the numbers together, and all the variables

3v-(19v-15)-11=0

We get rid of parentheses

3v-19v+15-11=0

We add all the numbers together, and all the variables

-16v+4=0

We move all terms containing v to the left, all other terms to the right

-16v=-4

v=-4/-16

v=1/4

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