3(v-2)=5v+7-2(-2v-1)

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Solution for 3(v-2)=5v+7-2(-2v-1) equation: 



3(v-2)=5v+7-2(-2v-1)

We move all terms to the left:

3(v-2)-(5v+7-2(-2v-1))=0

We multiply parentheses

3v-(5v+7-2(-2v-1))-6=0



We calculate terms in parentheses: -(5v+7-2(-2v-1)), so:

5v+7-2(-2v-1)

determiningTheFunctionDomain
5v-2(-2v-1)+7

We multiply parentheses

5v+4v+2+7

We add all the numbers together, and all the variables

9v+9

Back to the equation:

-(9v+9)



We get rid of parentheses

3v-9v-9-6=0

We add all the numbers together, and all the variables

-6v-15=0

We move all terms containing v to the left, all other terms to the right

-6v=15

v=15/-6

v=-2+1/2

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