3(v-2)=7v+1-2(-4v-4)

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Solution for 3(v-2)=7v+1-2(-4v-4) equation: 



3(v-2)=7v+1-2(-4v-4)

We move all terms to the left:

3(v-2)-(7v+1-2(-4v-4))=0

We multiply parentheses

3v-(7v+1-2(-4v-4))-6=0



We calculate terms in parentheses: -(7v+1-2(-4v-4)), so:

7v+1-2(-4v-4)

determiningTheFunctionDomain
7v-2(-4v-4)+1

We multiply parentheses

7v+8v+8+1

We add all the numbers together, and all the variables

15v+9

Back to the equation:

-(15v+9)



We get rid of parentheses

3v-15v-9-6=0

We add all the numbers together, and all the variables

-12v-15=0

We move all terms containing v to the left, all other terms to the right

-12v=15

v=15/-12

v=-1+1/4

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