3(v-2)=7v+6-4(-2v-1)

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Solution for 3(v-2)=7v+6-4(-2v-1) equation: 



3(v-2)=7v+6-4(-2v-1)

We move all terms to the left:

3(v-2)-(7v+6-4(-2v-1))=0

We multiply parentheses

3v-(7v+6-4(-2v-1))-6=0



We calculate terms in parentheses: -(7v+6-4(-2v-1)), so:

7v+6-4(-2v-1)

determiningTheFunctionDomain
7v-4(-2v-1)+6

We multiply parentheses

7v+8v+4+6

We add all the numbers together, and all the variables

15v+10

Back to the equation:

-(15v+10)



We get rid of parentheses

3v-15v-10-6=0

We add all the numbers together, and all the variables

-12v-16=0

We move all terms containing v to the left, all other terms to the right

-12v=16

v=16/-12

v=-1+1/3

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