3(v-2)=9v+2-4(-3-1)

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Solution for 3(v-2)=9v+2-4(-3-1) equation: 



3(v-2)=9v+2-4(-3-1)

We move all terms to the left:

3(v-2)-(9v+2-4(-3-1))=0

We add all the numbers together, and all the variables

3(v-2)-(9v+2-4(-4))=0

We multiply parentheses

3v-(9v+2-4(-4))-6=0



We calculate terms in parentheses: -(9v+2-4(-4)), so:

9v+2-4(-4)

We add all the numbers together, and all the variables

9v+18

Back to the equation:

-(9v+18)



We get rid of parentheses

3v-9v-18-6=0

We add all the numbers together, and all the variables

-6v-24=0

We move all terms containing v to the left, all other terms to the right

-6v=24

v=24/-6

v=-4

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