3(v-3)=5v+4-2(-2v-1)

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Solution for 3(v-3)=5v+4-2(-2v-1) equation:



3(v-3)=5v+4-2(-2v-1)
We move all terms to the left:
3(v-3)-(5v+4-2(-2v-1))=0
We multiply parentheses
3v-(5v+4-2(-2v-1))-9=0
We calculate terms in parentheses: -(5v+4-2(-2v-1)), so:
5v+4-2(-2v-1)
determiningTheFunctionDomain 5v-2(-2v-1)+4
We multiply parentheses
5v+4v+2+4
We add all the numbers together, and all the variables
9v+6
Back to the equation:
-(9v+6)
We get rid of parentheses
3v-9v-6-9=0
We add all the numbers together, and all the variables
-6v-15=0
We move all terms containing v to the left, all other terms to the right
-6v=15
v=15/-6
v=-2+1/2

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