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3(v-4)=2(2v-5)
We move all terms to the left:
3(v-4)-(2(2v-5))=0
We multiply parentheses
3v-(2(2v-5))-12=0
We calculate terms in parentheses: -(2(2v-5)), so:We get rid of parentheses
2(2v-5)
We multiply parentheses
4v-10
Back to the equation:
-(4v-10)
3v-4v+10-12=0
We add all the numbers together, and all the variables
-1v-2=0
We move all terms containing v to the left, all other terms to the right
-v=2
v=2/-1
v=-2
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