3(v-4)=3v+2-4(-3v-1)

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Solution for 3(v-4)=3v+2-4(-3v-1) equation:



3(v-4)=3v+2-4(-3v-1)
We move all terms to the left:
3(v-4)-(3v+2-4(-3v-1))=0
We multiply parentheses
3v-(3v+2-4(-3v-1))-12=0
We calculate terms in parentheses: -(3v+2-4(-3v-1)), so:
3v+2-4(-3v-1)
determiningTheFunctionDomain 3v-4(-3v-1)+2
We multiply parentheses
3v+12v+4+2
We add all the numbers together, and all the variables
15v+6
Back to the equation:
-(15v+6)
We get rid of parentheses
3v-15v-6-12=0
We add all the numbers together, and all the variables
-12v-18=0
We move all terms containing v to the left, all other terms to the right
-12v=18
v=18/-12
v=-1+1/2

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