3(v-4)=5v+1-3(-4v-1)

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Solution for 3(v-4)=5v+1-3(-4v-1) equation: 



3(v-4)=5v+1-3(-4v-1)

We move all terms to the left:

3(v-4)-(5v+1-3(-4v-1))=0

We multiply parentheses

3v-(5v+1-3(-4v-1))-12=0



We calculate terms in parentheses: -(5v+1-3(-4v-1)), so:

5v+1-3(-4v-1)

determiningTheFunctionDomain
5v-3(-4v-1)+1

We multiply parentheses

5v+12v+3+1

We add all the numbers together, and all the variables

17v+4

Back to the equation:

-(17v+4)



We get rid of parentheses

3v-17v-4-12=0

We add all the numbers together, and all the variables

-14v-16=0

We move all terms containing v to the left, all other terms to the right

-14v=16

v=16/-14

v=-1+1/7

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