3(v-5)-1=-2(-8v+1)-7v

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Solution for 3(v-5)-1=-2(-8v+1)-7v equation: 



3(v-5)-1=-2(-8v+1)-7v

We move all terms to the left:

3(v-5)-1-(-2(-8v+1)-7v)=0

We multiply parentheses

3v-(-2(-8v+1)-7v)-15-1=0



We calculate terms in parentheses: -(-2(-8v+1)-7v), so:

-2(-8v+1)-7v

We add all the numbers together, and all the variables

-7v-2(-8v+1)

We multiply parentheses

-7v+16v-2

We add all the numbers together, and all the variables

9v-2

Back to the equation:

-(9v-2)



We add all the numbers together, and all the variables

3v-(9v-2)-16=0

We get rid of parentheses

3v-9v+2-16=0

We add all the numbers together, and all the variables

-6v-14=0

We move all terms containing v to the left, all other terms to the right

-6v=14

v=14/-6

v=-2+1/3

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