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3(v-6)+2=3(v+2)
We move all terms to the left:
3(v-6)+2-(3(v+2))=0
We multiply parentheses
3v-(3(v+2))-18+2=0
We calculate terms in parentheses: -(3(v+2)), so:We add all the numbers together, and all the variables
3(v+2)
We multiply parentheses
3v+6
Back to the equation:
-(3v+6)
3v-(3v+6)-16=0
We get rid of parentheses
3v-3v-6-16=0
We add all the numbers together, and all the variables
-22!=0
There is no solution for this equation
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