3(v-9)=1+2(3v-2)

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Solution for 3(v-9)=1+2(3v-2) equation: 



3(v-9)=1+2(3v-2)

We move all terms to the left:

3(v-9)-(1+2(3v-2))=0

We multiply parentheses

3v-(1+2(3v-2))-27=0



We calculate terms in parentheses: -(1+2(3v-2)), so:

1+2(3v-2)

determiningTheFunctionDomain
2(3v-2)+1

We multiply parentheses

6v-4+1

We add all the numbers together, and all the variables

6v-3

Back to the equation:

-(6v-3)



We get rid of parentheses

3v-6v+3-27=0

We add all the numbers together, and all the variables

-3v-24=0

We move all terms containing v to the left, all other terms to the right

-3v=24

v=24/-3

v=-8

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