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3(w+1)+2w=5(w-1)+1
We move all terms to the left:
3(w+1)+2w-(5(w-1)+1)=0
We add all the numbers together, and all the variables
2w+3(w+1)-(5(w-1)+1)=0
We multiply parentheses
2w+3w-(5(w-1)+1)+3=0
We calculate terms in parentheses: -(5(w-1)+1), so:We add all the numbers together, and all the variables
5(w-1)+1
We multiply parentheses
5w-5+1
We add all the numbers together, and all the variables
5w-4
Back to the equation:
-(5w-4)
5w-(5w-4)+3=0
We get rid of parentheses
5w-5w+4+3=0
We add all the numbers together, and all the variables
7!=0
There is no solution for this equation
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