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3(w+1)=6-2(1-2w)
We move all terms to the left:
3(w+1)-(6-2(1-2w))=0
We add all the numbers together, and all the variables
3(w+1)-(6-2(-2w+1))=0
We multiply parentheses
3w-(6-2(-2w+1))+3=0
We calculate terms in parentheses: -(6-2(-2w+1)), so:We get rid of parentheses
6-2(-2w+1)
determiningTheFunctionDomain -2(-2w+1)+6
We multiply parentheses
4w-2+6
We add all the numbers together, and all the variables
4w+4
Back to the equation:
-(4w+4)
3w-4w-4+3=0
We add all the numbers together, and all the variables
-1w-1=0
We move all terms containing w to the left, all other terms to the right
-w=1
w=1/-1
w=-1
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