3(w+1)=6-2(1-2w)

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Solution for 3(w+1)=6-2(1-2w) equation: 



3(w+1)=6-2(1-2w)

We move all terms to the left:

3(w+1)-(6-2(1-2w))=0

We add all the numbers together, and all the variables

3(w+1)-(6-2(-2w+1))=0

We multiply parentheses

3w-(6-2(-2w+1))+3=0



We calculate terms in parentheses: -(6-2(-2w+1)), so:

6-2(-2w+1)

determiningTheFunctionDomain
-2(-2w+1)+6

We multiply parentheses

4w-2+6

We add all the numbers together, and all the variables

4w+4

Back to the equation:

-(4w+4)



We get rid of parentheses

3w-4w-4+3=0

We add all the numbers together, and all the variables

-1w-1=0

We move all terms containing w to the left, all other terms to the right

-w=1

w=1/-1

w=-1

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