3(w+2)(-w-3)=0

Solution for 3(w+2)(-w-3)=0 equation:

3(w+2)(-w-3)=0

We add all the numbers together, and all the variables

3(w+2)(-1w-3)=0

We multiply parentheses ..

3(-1w^2-3w-2w-6)=0

We multiply parentheses

-3w^2-9w-6w-18=0

We add all the numbers together, and all the variables

-3w^2-15w-18=0

a = -3; b = -15; c = -18;
Δ = b2-4ac
Δ = -152-4·(-3)·(-18)
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-3}{2*-3}=\frac{12}{-6}
=-2
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+3}{2*-3}=\frac{18}{-6}
=-3
$