3(w+2)+2w=7(w+1)+9

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Solution for 3(w+2)+2w=7(w+1)+9 equation: 



3(w+2)+2w=7(w+1)+9

We move all terms to the left:

3(w+2)+2w-(7(w+1)+9)=0

We add all the numbers together, and all the variables

2w+3(w+2)-(7(w+1)+9)=0

We multiply parentheses

2w+3w-(7(w+1)+9)+6=0



We calculate terms in parentheses: -(7(w+1)+9), so:

7(w+1)+9

We multiply parentheses

7w+7+9

We add all the numbers together, and all the variables

7w+16

Back to the equation:

-(7w+16)



We add all the numbers together, and all the variables

5w-(7w+16)+6=0

We get rid of parentheses

5w-7w-16+6=0

We add all the numbers together, and all the variables

-2w-10=0

We move all terms containing w to the left, all other terms to the right

-2w=10

w=10/-2

w=-5

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