3(w+2)+4=5(w+1)+w

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Solution for 3(w+2)+4=5(w+1)+w equation: 



3(w+2)+4=5(w+1)+w

We move all terms to the left:

3(w+2)+4-(5(w+1)+w)=0

We multiply parentheses

3w-(5(w+1)+w)+6+4=0



We calculate terms in parentheses: -(5(w+1)+w), so:

5(w+1)+w

We add all the numbers together, and all the variables

w+5(w+1)

We multiply parentheses

w+5w+5

We add all the numbers together, and all the variables

6w+5

Back to the equation:

-(6w+5)



We add all the numbers together, and all the variables

3w-(6w+5)+10=0

We get rid of parentheses

3w-6w-5+10=0

We add all the numbers together, and all the variables

-3w+5=0

We move all terms containing w to the left, all other terms to the right

-3w=-5

w=-5/-3

w=1+2/3

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