3(w+2)+4=5(w-1)

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Solution for 3(w+2)+4=5(w-1) equation: 



3(w+2)+4=5(w-1)

We move all terms to the left:

3(w+2)+4-(5(w-1))=0

We multiply parentheses

3w-(5(w-1))+6+4=0



We calculate terms in parentheses: -(5(w-1)), so:

5(w-1)

We multiply parentheses

5w-5

Back to the equation:

-(5w-5)



We add all the numbers together, and all the variables

3w-(5w-5)+10=0

We get rid of parentheses

3w-5w+5+10=0

We add all the numbers together, and all the variables

-2w+15=0

We move all terms containing w to the left, all other terms to the right

-2w=-15

w=-15/-2

w=7+1/2

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