3(w+2)+4=5(w-1)-2

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Solution for 3(w+2)+4=5(w-1)-2 equation: 



3(w+2)+4=5(w-1)-2

We move all terms to the left:

3(w+2)+4-(5(w-1)-2)=0

We multiply parentheses

3w-(5(w-1)-2)+6+4=0



We calculate terms in parentheses: -(5(w-1)-2), so:

5(w-1)-2

We multiply parentheses

5w-5-2

We add all the numbers together, and all the variables

5w-7

Back to the equation:

-(5w-7)



We add all the numbers together, and all the variables

3w-(5w-7)+10=0

We get rid of parentheses

3w-5w+7+10=0

We add all the numbers together, and all the variables

-2w+17=0

We move all terms containing w to the left, all other terms to the right

-2w=-17

w=-17/-2

w=8+1/2

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