3(w+2)+w=4(w-1)

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Solution for 3(w+2)+w=4(w-1) equation: 



3(w+2)+w=4(w-1)

We move all terms to the left:

3(w+2)+w-(4(w-1))=0

We add all the numbers together, and all the variables

w+3(w+2)-(4(w-1))=0

We multiply parentheses

w+3w-(4(w-1))+6=0



We calculate terms in parentheses: -(4(w-1)), so:

4(w-1)

We multiply parentheses

4w-4

Back to the equation:

-(4w-4)



We add all the numbers together, and all the variables

4w-(4w-4)+6=0

We get rid of parentheses

4w-4w+4+6=0

We add all the numbers together, and all the variables

10!=0

There is no solution for this equation

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