3(w+2)-(12-w)=4w-6

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Solution for 3(w+2)-(12-w)=4w-6 equation:


Simplifying
3(w + 2) + -1(12 + -1w) = 4w + -6

Reorder the terms:
3(2 + w) + -1(12 + -1w) = 4w + -6
(2 * 3 + w * 3) + -1(12 + -1w) = 4w + -6
(6 + 3w) + -1(12 + -1w) = 4w + -6
6 + 3w + (12 * -1 + -1w * -1) = 4w + -6
6 + 3w + (-12 + 1w) = 4w + -6

Reorder the terms:
6 + -12 + 3w + 1w = 4w + -6

Combine like terms: 6 + -12 = -6
-6 + 3w + 1w = 4w + -6

Combine like terms: 3w + 1w = 4w
-6 + 4w = 4w + -6

Reorder the terms:
-6 + 4w = -6 + 4w

Add '6' to each side of the equation.
-6 + 6 + 4w = -6 + 6 + 4w

Combine like terms: -6 + 6 = 0
0 + 4w = -6 + 6 + 4w
4w = -6 + 6 + 4w

Combine like terms: -6 + 6 = 0
4w = 0 + 4w
4w = 4w

Add '-4w' to each side of the equation.
4w + -4w = 4w + -4w

Combine like terms: 4w + -4w = 0
0 = 4w + -4w

Combine like terms: 4w + -4w = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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