3(w+2)-2=2(w-1)+5

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Solution for 3(w+2)-2=2(w-1)+5 equation: 



3(w+2)-2=2(w-1)+5

We move all terms to the left:

3(w+2)-2-(2(w-1)+5)=0

We multiply parentheses

3w-(2(w-1)+5)+6-2=0



We calculate terms in parentheses: -(2(w-1)+5), so:

2(w-1)+5

We multiply parentheses

2w-2+5

We add all the numbers together, and all the variables

2w+3

Back to the equation:

-(2w+3)



We add all the numbers together, and all the variables

3w-(2w+3)+4=0

We get rid of parentheses

3w-2w-3+4=0

We add all the numbers together, and all the variables

w+1=0

We move all terms containing w to the left, all other terms to the right

w=-1

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