3(w+2)-w=2(w+1)+5

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Solution for 3(w+2)-w=2(w+1)+5 equation: 



3(w+2)-w=2(w+1)+5

We move all terms to the left:

3(w+2)-w-(2(w+1)+5)=0

We add all the numbers together, and all the variables

-1w+3(w+2)-(2(w+1)+5)=0

We multiply parentheses

-1w+3w-(2(w+1)+5)+6=0



We calculate terms in parentheses: -(2(w+1)+5), so:

2(w+1)+5

We multiply parentheses

2w+2+5

We add all the numbers together, and all the variables

2w+7

Back to the equation:

-(2w+7)



We add all the numbers together, and all the variables

2w-(2w+7)+6=0

We get rid of parentheses

2w-2w-7+6=0

We add all the numbers together, and all the variables

-1!=0

There is no solution for this equation

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