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3(w+2)-w=2(w+1)=5
We move all terms to the left:
3(w+2)-w-(2(w+1))=0
We add all the numbers together, and all the variables
-1w+3(w+2)-(2(w+1))=0
We multiply parentheses
-1w+3w-(2(w+1))+6=0
We calculate terms in parentheses: -(2(w+1)), so:We add all the numbers together, and all the variables
2(w+1)
We multiply parentheses
2w+2
Back to the equation:
-(2w+2)
2w-(2w+2)+6=0
We get rid of parentheses
2w-2w-2+6=0
We add all the numbers together, and all the variables
4!=0
There is no solution for this equation
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