3(w+2)-w=2(w-1)+5

Solution for 3(w+2)-w=2(w-1)+5 equation:

Simplifying
3(w + 2) + -1w = 2(w + -1) + 5

Reorder the terms:
3(2 + w) + -1w = 2(w + -1) + 5
(2 * 3 + w * 3) + -1w = 2(w + -1) + 5
(6 + 3w) + -1w = 2(w + -1) + 5

Combine like terms: 3w + -1w = 2w
6 + 2w = 2(w + -1) + 5

Reorder the terms:
6 + 2w = 2(-1 + w) + 5
6 + 2w = (-1 * 2 + w * 2) + 5
6 + 2w = (-2 + 2w) + 5

Reorder the terms:
6 + 2w = -2 + 5 + 2w

Combine like terms: -2 + 5 = 3
6 + 2w = 3 + 2w

Add '-2w' to each side of the equation.
6 + 2w + -2w = 3 + 2w + -2w

Combine like terms: 2w + -2w = 0
6 + 0 = 3 + 2w + -2w
6 = 3 + 2w + -2w

Combine like terms: 2w + -2w = 0
6 = 3 + 0
6 = 3

Solving
6 = 3

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.