3(w+3)+w=2(w+1)+3

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Solution for 3(w+3)+w=2(w+1)+3 equation: 



3(w+3)+w=2(w+1)+3

We move all terms to the left:

3(w+3)+w-(2(w+1)+3)=0

We add all the numbers together, and all the variables

w+3(w+3)-(2(w+1)+3)=0

We multiply parentheses

w+3w-(2(w+1)+3)+9=0



We calculate terms in parentheses: -(2(w+1)+3), so:

2(w+1)+3

We multiply parentheses

2w+2+3

We add all the numbers together, and all the variables

2w+5

Back to the equation:

-(2w+5)



We add all the numbers together, and all the variables

4w-(2w+5)+9=0

We get rid of parentheses

4w-2w-5+9=0

We add all the numbers together, and all the variables

2w+4=0

We move all terms containing w to the left, all other terms to the right

2w=-4

w=-4/2

w=-2

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