3(w+5)+w=2(w-1)+3

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Solution for 3(w+5)+w=2(w-1)+3 equation: 



3(w+5)+w=2(w-1)+3

We move all terms to the left:

3(w+5)+w-(2(w-1)+3)=0

We add all the numbers together, and all the variables

w+3(w+5)-(2(w-1)+3)=0

We multiply parentheses

w+3w-(2(w-1)+3)+15=0



We calculate terms in parentheses: -(2(w-1)+3), so:

2(w-1)+3

We multiply parentheses

2w-2+3

We add all the numbers together, and all the variables

2w+1

Back to the equation:

-(2w+1)



We add all the numbers together, and all the variables

4w-(2w+1)+15=0

We get rid of parentheses

4w-2w-1+15=0

We add all the numbers together, and all the variables

2w+14=0

We move all terms containing w to the left, all other terms to the right

2w=-14

w=-14/2

w=-7

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