3(w+5)3w=20

Solution for 3(w+5)3w=20 equation:

3(w+5)3w=20

We move all terms to the left:

3(w+5)3w-(20)=0

We multiply parentheses

9w^2+45w-20=0

a = 9; b = 45; c = -20;
Δ = b2-4ac
Δ = 452-4·9·(-20)
Δ = 2745
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2745}=\sqrt{9*305}=\sqrt{9}*\sqrt{305}=3\sqrt{305}$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-3\sqrt{305}}{2*9}=\frac{-45-3\sqrt{305}}{18}
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+3\sqrt{305}}{2*9}=\frac{-45+3\sqrt{305}}{18}
$