3(w-3)=7w+1-2(-4w-4)

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Solution for 3(w-3)=7w+1-2(-4w-4) equation:



3(w-3)=7w+1-2(-4w-4)
We move all terms to the left:
3(w-3)-(7w+1-2(-4w-4))=0
We multiply parentheses
3w-(7w+1-2(-4w-4))-9=0
We calculate terms in parentheses: -(7w+1-2(-4w-4)), so:
7w+1-2(-4w-4)
determiningTheFunctionDomain 7w-2(-4w-4)+1
We multiply parentheses
7w+8w+8+1
We add all the numbers together, and all the variables
15w+9
Back to the equation:
-(15w+9)
We get rid of parentheses
3w-15w-9-9=0
We add all the numbers together, and all the variables
-12w-18=0
We move all terms containing w to the left, all other terms to the right
-12w=18
w=18/-12
w=-1+1/2

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