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3(w-5)=2(5+w)
We move all terms to the left:
3(w-5)-(2(5+w))=0
We add all the numbers together, and all the variables
3(w-5)-(2(w+5))=0
We multiply parentheses
3w-(2(w+5))-15=0
We calculate terms in parentheses: -(2(w+5)), so:We get rid of parentheses
2(w+5)
We multiply parentheses
2w+10
Back to the equation:
-(2w+10)
3w-2w-10-15=0
We add all the numbers together, and all the variables
w-25=0
We move all terms containing w to the left, all other terms to the right
w=25
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