3(x)=19x+11

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Solution for 3(x)=19x+11 equation: 



3(x)=19x+11

We move all terms to the left:

3(x)-(19x+11)=0

We get rid of parentheses

3x-19x-11=0

We add all the numbers together, and all the variables

-16x-11=0

We move all terms containing x to the left, all other terms to the right

-16x=11

x=11/-16

x=-11/16

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