3(x+(x+1))=(x(x+1))-11

Solution for 3(x+(x+1))=(x(x+1))-11 equation:

3(x+(x+1))=(x(x+1))-11

We move all terms to the left:

3(x+(x+1))-((x(x+1))-11)=0


We calculate terms in parentheses: -((x(x+1))-11), so:

(x(x+1))-11


We calculate terms in parentheses: +(x(x+1)), so:

x(x+1)

We multiply parentheses

x^2+x

Back to the equation:

+(x^2+x)


We get rid of parentheses

x^2+x-11

Back to the equation:

-(x^2+x-11)


We get rid of parentheses

-x^2+3(x+(x+1))-x+11=0

We add all the numbers together, and all the variables

-1x^2-1x+3(x+(x+1))+11=0

We move all terms containing x to the left, all other terms to the right

-1x^2-1x+3(x+(x+1))=-11