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3(x+)-(2x-3)=12
We move all terms to the left:
3(x+)-(2x-3)-(12)=0
We add all the numbers together, and all the variables
3(+x)-(2x-3)-12=0
We multiply parentheses
3x-(2x-3)-12=0
We get rid of parentheses
3x-2x+3-12=0
We add all the numbers together, and all the variables
x-9=0
We move all terms containing x to the left, all other terms to the right
x=9
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