3(x+-2)+-4(2+3x)=x+10

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Solution for 3(x+-2)+-4(2+3x)=x+10 equation: 



3(x+-2)+-4(2+3x)=x+10

We move all terms to the left:

3(x+-2)+-4(2+3x)-(x+10)=0

We add all the numbers together, and all the variables

3(x-2)-4(3x+2)-(x+10)+=0

We add all the numbers together, and all the variables

3(x-2)-4(3x+2)-(x+10)=0

We multiply parentheses

3x-12x-(x+10)-6-8=0

We get rid of parentheses

3x-12x-x-10-6-8=0

We add all the numbers together, and all the variables

-10x-24=0

We move all terms containing x to the left, all other terms to the right

-10x=24

x=24/-10

x=-2+2/5

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