3(x+-2)+-4(2+3x)=x+10

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Solution for 3(x+-2)+-4(2+3x)=x+10 equation:



3(x+-2)+-4(2+3x)=x+10
We move all terms to the left:
3(x+-2)+-4(2+3x)-(x+10)=0
We add all the numbers together, and all the variables
3(x-2)-4(3x+2)-(x+10)+=0
We add all the numbers together, and all the variables
3(x-2)-4(3x+2)-(x+10)=0
We multiply parentheses
3x-12x-(x+10)-6-8=0
We get rid of parentheses
3x-12x-x-10-6-8=0
We add all the numbers together, and all the variables
-10x-24=0
We move all terms containing x to the left, all other terms to the right
-10x=24
x=24/-10
x=-2+2/5

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