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3(x+-2)+4=-1+3(1-x)
We move all terms to the left:
3(x+-2)+4-(-1+3(1-x))=0
We add all the numbers together, and all the variables
3(x-2)-(-1+3(-1x+1))+4=0
We multiply parentheses
3x-(-1+3(-1x+1))-6+4=0
We calculate terms in parentheses: -(-1+3(-1x+1)), so:We add all the numbers together, and all the variables
-1+3(-1x+1)
determiningTheFunctionDomain 3(-1x+1)-1
We multiply parentheses
-3x+3-1
We add all the numbers together, and all the variables
-3x+2
Back to the equation:
-(-3x+2)
3x-(-3x+2)-2=0
We get rid of parentheses
3x+3x-2-2=0
We add all the numbers together, and all the variables
6x-4=0
We move all terms containing x to the left, all other terms to the right
6x=4
x=4/6
x=2/3
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