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3(x+-4)+-12=2(x+-6)+7
We move all terms to the left:
3(x+-4)+-12-(2(x+-6)+7)=0
We add all the numbers together, and all the variables
3(x-4)-(2(x-6)+7)-12+=0
We add all the numbers together, and all the variables
3(x-4)-(2(x-6)+7)=0
We multiply parentheses
3x-(2(x-6)+7)-12=0
We calculate terms in parentheses: -(2(x-6)+7), so:We get rid of parentheses
2(x-6)+7
We multiply parentheses
2x-12+7
We add all the numbers together, and all the variables
2x-5
Back to the equation:
-(2x-5)
3x-2x+5-12=0
We add all the numbers together, and all the variables
x-7=0
We move all terms containing x to the left, all other terms to the right
x=7
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