3(x+-4)+-16=2(x+-8)+6

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Solution for 3(x+-4)+-16=2(x+-8)+6 equation: 



3(x+-4)+-16=2(x+-8)+6

We move all terms to the left:

3(x+-4)+-16-(2(x+-8)+6)=0

We add all the numbers together, and all the variables

3(x-4)-(2(x-8)+6)-16+=0

We add all the numbers together, and all the variables

3(x-4)-(2(x-8)+6)=0

We multiply parentheses

3x-(2(x-8)+6)-12=0



We calculate terms in parentheses: -(2(x-8)+6), so:

2(x-8)+6

We multiply parentheses

2x-16+6

We add all the numbers together, and all the variables

2x-10

Back to the equation:

-(2x-10)



We get rid of parentheses

3x-2x+10-12=0

We add all the numbers together, and all the variables

x-2=0

We move all terms containing x to the left, all other terms to the right

x=2

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