3(x+-41)+-(10)=50

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Solution for 3(x+-41)+-(10)=50 equation:



3(x+-41)+-(10)=50
We move all terms to the left:
3(x+-41)+-(10)-(50)=0
determiningTheFunctionDomain 3(x+-41)-10-50+=0
We add all the numbers together, and all the variables
3(x-41)-10-50+=0
We add all the numbers together, and all the variables
3(x-41)=0
We multiply parentheses
3x-123=0
We move all terms containing x to the left, all other terms to the right
3x=123
x=123/3
x=41

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