3(x+-41)+-(10)=50

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Solution for 3(x+-41)+-(10)=50 equation: 



3(x+-41)+-(10)=50

We move all terms to the left:

3(x+-41)+-(10)-(50)=0

determiningTheFunctionDomain
3(x+-41)-10-50+=0

We add all the numbers together, and all the variables

3(x-41)-10-50+=0

We add all the numbers together, and all the variables

3(x-41)=0

We multiply parentheses

3x-123=0

We move all terms containing x to the left, all other terms to the right

3x=123

x=123/3

x=41

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