3(x+1)(x-1)=(3x-1)(x-2)+9

Solution for 3(x+1)(x-1)=(3x-1)(x-2)+9 equation:

3(x+1)(x-1)=(3x-1)(x-2)+9

We move all terms to the left:

3(x+1)(x-1)-((3x-1)(x-2)+9)=0

We use the square of the difference formula

x^2-((3x-1)(x-2)+9)-1=0

We multiply parentheses ..

x^2-((+3x^2-6x-1x+2)+9)-1=0


We calculate terms in parentheses: -((+3x^2-6x-1x+2)+9), so:

(+3x^2-6x-1x+2)+9

We get rid of parentheses

3x^2-6x-1x+2+9

We add all the numbers together, and all the variables

3x^2-7x+11

Back to the equation:

-(3x^2-7x+11)


We get rid of parentheses

x^2-3x^2+7x-11-1=0

We add all the numbers together, and all the variables

-2x^2+7x-12=0

a = -2; b = 7; c = -12;
Δ = b2-4ac
Δ = 72-4·(-2)·(-12)
Δ = -47
Delta is less than zero, so there is no solution for the equation